5-9m/m^2-4=0

Solution for 5-9m/m^2-4=0 equation:

5-9m/m^2-4=0


Domain of the equation: m^2!=0

m^2!=0/

m^2!=√0

m!=0

m∈R


We add all the numbers together, and all the variables

-9m/m^2+1=0

We multiply all the terms by the denominator


-9m+1*m^2=0

We add all the numbers together, and all the variables

m^2-9m=0

a = 1; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·1·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*1}=\frac{0}{2}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*1}=\frac{18}{2}
=9
$